To answer this mathematical pleasantry, which belongs as much to
the physical part of astronomy as to mechanics, we must observe:
1st. That the gravity of bodies decreases in the inverse ratio of the
squares of their distance from the centre of the earth. A body, for example,
raised to the distance of a semi-diameter of the earth above its surface,
being then at the distance of twice the radius, will weigh only 1/4 of
what it weighed at the surface.
2d. If we suppose that this body partakes with the rest of the earth in
the rotary motion which it has around the axis, this gravity will be still
diminished by the centrifugal force; which, on the supposition that unequal
circles are described in the same time, will be as their radii. Hence
at a double distance from the earth this force will be double, and will
deduct twice as much from the gravity as the surface of the earth. But it
has been found, that under the equator the centrifugal force lessens the
natural gravity of bodies 1/289th part
3d. In all places, on either side of the equator, the centrifugal force
being less, and acting against the gravity in an oblique direction, destroys
a less portion, in the ratio of the square of the cosine of the latitude to the
square of radius.
These things being premised, we may determine at what height
above the surface of the earth a body, participating in its diurnal motion
in any given latitude, ought to be to have no gravity.
But it is found by analysis that under the equator, where the diminution
of gravity at the surface of the earth, occasioned by the centrifugal
force, is exactly 1/289, the required height, counting from the centre of
the earth, ought to be 2891/3, or 6 semi-diameters of our globe plus
65/100, or 5 semi-diameters and 65/100 above the surface.
Under the latitude of 30 degrees, which is nearly that of the plains of
Mesopotamia, where the descendants of Noah first assembled, and vainly
attempted, as we learn from the Scriptures, to raise a monument of their
folly, it will be found that the height above the surface of the earth ought
to have been 6 27/100 semi-diameters of the earth.
Under the latitude of 60 degrees, this height above the surface of the
earth ought to have been 9 47/100 semi-diameters of the earth.
Under the pole this distance might be infinite; because in that part of
the earth there is no centrifugal force, since bodies at the pole only turn
round themselves.
NOTES AND REFERENCES
1
The question and answer are from Recreations in Mathematics and
Natural Philosophy: containing amusing dissertations and enquiries
concerning a variety of subjects the moset remarkable and proper to
excite curiosity and attention to the whole range of the mathematical
and philosophical sciences. M. Ozanam. Enlarged by M. Montucla.
Translated into English by Chas. Hutton. Vol. 4 (of 4). (London: G.
Kearsley), 1803. Pp. 40-42.